Allegiant Air G4993 Flight Status Tracker
G4993 is a domestic flight operated by Allegiant Air. G4993 is departing from Clearwater (PIE), United States and arriving at Knoxville (TYS), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 2 hours 55 minutes. Get the latest status of G4993 / AAY993 here.
Update on May 3, 2024, 9:13 p.m.
Lastest Status
N/A
| PIE | TYS |
Distance: 883.79 km / 549.16 miles or 477.21 nautical miles.
Departure St. Pete - Clearwater International Airport
Scheduled Departure: 3:20 p.m.
Departure Terminal : N/A Gate None
Arrival Knoxville Airport
Scheduled Arrival: 6:31 p.m.
Arrival Terminal : 4 Gate None
Flight G4993 detail information
| Type | Domestic Flight |
| Route | Departure Clearwater (PIE), United States and arriving at Knoxville (TYS), United States |
| Airlines | Allegiant Air (G4) |
| Aircraft | A320 |
| Flight Duration | 2 hours 55 minutes |
| Flight Distance | 883.79 km /549.16 miles |
| Operating Days | Thursday |
Find more flight status
G4993 Airports
| Departures |
|---|
| Airport: St. Pete - Clearwater International Airport, United States |
| ICAO Code: PIE |
| PIE Current time: 06:54 05-May-2024 |
| Arrivals |
| Airport: Knoxville Airport, United States |
| ICAO Code: TYS |
| TYS Current time: 06:54 05-May-2024 |