Allegiant Air G4433 Flight Status Tracker

G4433 is a domestic flight operated by Allegiant Air. G4433 is departing from Clearwater (PIE), United States and arriving at Knoxville (TYS), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 3 hours 30 minutes. Get the latest status of G4433 / AAY433 here.

Update on April 22, 2024, 9:54 p.m.

Lastest Status

N/A
G4 Flight Status
PIE
Departure
St. Pete - Clearwater International Airport
Scheduled Departure:
7 a.m.
Departure Terminal:
N/A Gate None
Flight Status
Distance:
883.79 km / 549.16 miles or 477.21 nautical miles.
TYS
Arrival
Knoxville Airport
Scheduled Arrival:
8:23 a.m.
Departure Terminal:
1 Gate None

Flight G4433 detail information

  • Type Domestic Flight
  • Route Departure Clearwater (PIE), United States and arriving at Knoxville (TYS), United States
  • Airlines Allegiant Air (G4)
  • Aircraft A320
  • Flight Duration 3 hours 30 minutes
  • Flight Distance 883.79 km /549.16 miles
  • Operating Days Monday, Friday

G4433 Airports

Departures
  • Airport: St. Pete - Clearwater International Airport, United States
  • ICAO Code: PIE
  • PIE Current time: 16:49 24-Apr-2024
Arrivals
  • Airport: Knoxville Airport, United States
  • ICAO Code: TYS
  • TYS Current time: 16:49 24-Apr-2024