Allegiant Air G49504 Flight Status Tracker
G49504 is a domestic flight operated by Allegiant Air. G49504 is departing from Clearwater (PIE), United States and arriving at Knoxville (TYS), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 0 minutes. Get the latest status of G49504 / AAY9504 here.
Update on April 11, 2022, 11:13 p.m.
Lastest Status
N/A
PIE
Departure
St. Pete - Clearwater International Airport
Scheduled Departure:
6 a.m.
Departure Terminal:
None Gate None
Distance:
883.79 km / 549.16 miles or 477.21 nautical miles.
TYS
Arrival
Knoxville Airport
Scheduled Arrival:
7:45 a.m.
Arrival Terminal:
None Gate None
Flight G49504 detail information
- Type Domestic Flight
- Route Departure Clearwater (PIE), United States and arriving at Knoxville (TYS), United States
- Airlines Allegiant Air (G4)
- Aircraft A320
- Flight Duration 0 minutes
- Flight Distance 883.79 km /549.16 miles
- Operating Days
G49504 Airports
Departures
- Airport: St. Pete - Clearwater International Airport, United States
- ICAO Code: PIE
- PIE Current time: 14:18 14-Jan-2026
Arrivals
- Airport: Knoxville Airport, United States
- ICAO Code: TYS
- TYS Current time: 14:18 14-Jan-2026
