Allegiant Air G49504 Flight Status Tracker
G49504 is a domestic flight operated by Allegiant Air. G49504 is departing from Clearwater (PIE), United States and arriving at Knoxville (TYS), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 0 minutes. Get the latest status of G49504 / AAY9504 here.
Update on April 11, 2022, 11:13 p.m.
Lastest Status
N/A
| PIE | TYS |
Distance: 883.79 km / 549.16 miles or 477.21 nautical miles.
Departure St. Pete - Clearwater International Airport
Scheduled Departure: 6 a.m.
Departure Terminal : None Gate None
Arrival Knoxville Airport
Scheduled Arrival: 7:45 a.m.
Arrival Terminal : None Gate None
Flight G49504 detail information
| Type | Domestic Flight |
| Route | Departure Clearwater (PIE), United States and arriving at Knoxville (TYS), United States |
| Airlines | Allegiant Air (G4) |
| Aircraft | A320 |
| Flight Duration | 0 minutes |
| Flight Distance | 883.79 km /549.16 miles |
| Operating Days |
Find more flight status
G49504 Airports
| Departures |
|---|
| Airport: St. Pete - Clearwater International Airport, United States |
| ICAO Code: PIE |
| PIE Current time: 16:05 14-Jan-2026 |
| Arrivals |
| Airport: Knoxville Airport, United States |
| ICAO Code: TYS |
| TYS Current time: 16:05 14-Jan-2026 |