Allegiant Air G4993 Flight Status Tracker
G4993 is a domestic flight operated by Allegiant Air. G4993 is departing from Clearwater (PIE), United States and arriving at Knoxville (TYS), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 2 hours 55 minutes. Get the latest status of G4993 / AAY993 here.
Update on March 31, 2024, 6:28 p.m.
Lastest Status
N/A
PIE
Departure
St. Pete - Clearwater International Airport
Scheduled Departure:
3:20 p.m.
Departure Terminal:
N/A Gate None
Distance:
883.79 km / 549.16 miles or 477.21 nautical miles.
TYS
Arrival
Knoxville Airport
Scheduled Arrival:
6:31 p.m.
Departure Terminal:
4 Gate None
Flight G4993 detail information
- Type Domestic Flight
- Route Departure Clearwater (PIE), United States and arriving at Knoxville (TYS), United States
- Airlines Allegiant Air (G4)
- Aircraft A320
- Flight Duration 2 hours 55 minutes
- Flight Distance 883.79 km /549.16 miles
- Operating Days Thursday
G4993 Airports
Departures
- Airport: St. Pete - Clearwater International Airport, United States
- ICAO Code: PIE
- PIE Current time: 19:25 25-Apr-2024
Arrivals
- Airport: Knoxville Airport, United States
- ICAO Code: TYS
- TYS Current time: 19:25 25-Apr-2024