Allegiant Air G4433 Flight Status Tracker
G4433 is a domestic flight operated by Allegiant Air. G4433 is departing from Clearwater (PIE), United States and arriving at Knoxville (TYS), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 3 hours 30 minutes. Get the latest status of G4433 / AAY433 here.
Update on Jan. 4, 2026, 8:57 a.m.
Lastest Status
N/A
| PIE | TYS |
Distance: 883.79 km / 549.16 miles or 477.21 nautical miles.
Departure St. Pete - Clearwater International Airport
Scheduled Departure: 7 a.m.
Departure Terminal : N/A Gate None
Arrival Knoxville Airport
Scheduled Arrival: 8:46 a.m.
Arrival Terminal : 1 Gate None
Flight G4433 detail information
| Type | Domestic Flight |
| Route | Departure Clearwater (PIE), United States and arriving at Knoxville (TYS), United States |
| Airlines | Allegiant Air (G4) |
| Aircraft | A320 |
| Flight Duration | 3 hours 30 minutes |
| Flight Distance | 883.79 km /549.16 miles |
| Operating Days | Monday, Friday |
Find more flight status
G4433 Airports
| Departures |
|---|
| Airport: St. Pete - Clearwater International Airport, United States |
| ICAO Code: PIE |
| PIE Current time: 21:57 14-Jan-2026 |
| Arrivals |
| Airport: Knoxville Airport, United States |
| ICAO Code: TYS |
| TYS Current time: 21:57 14-Jan-2026 |