American Airlines AA5007 Flight Status Tracker
AA5007 is a domestic flight operated by American Airlines. AA5007 is departing from Knoxville (TYS), United States and arriving at Charlotte (CLT), United States. The flight distance is about 284.56 km or 176.82 miles and flight time is 1 hours 8 minutes. Get the latest status of AA5007 / AAL5007 here.
Update on Feb. 24, 2024, 3:29 p.m.
Lastest Status
N/A
TYS | CLT |
Distance: 284.56 km / 176.82 miles or 153.65 nautical miles.
Departure Knoxville Airport
Scheduled Departure: 7:37 a.m.
Departure Terminal : 3 Gate None
Arrival Charlotte Douglas Airport
Scheduled Arrival: 10:07 a.m.
Arrival Terminal : 4 Gate None
Flight AA5007 detail information
Type | Domestic Flight |
Route | Departure Knoxville (TYS), United States and arriving at Charlotte (CLT), United States |
Airlines | American Airlines (AA) |
Aircraft | E145 |
Flight Duration | 1 hours 8 minutes |
Flight Distance | 284.56 km /176.82 miles |
Operating Days | Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday |
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AA5007 Airports
Departures |
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Airport: Knoxville Airport, United States |
ICAO Code: TYS |
TYS Current time: 23:11 28-Apr-2024 |
Arrivals |
Airport: Charlotte Douglas Airport, United States |
ICAO Code: CLT |
CLT Current time: 23:11 28-Apr-2024 |