American Airlines AA4910 Flight Status Tracker
AA4910 is a domestic flight operated by American Airlines. AA4910 is departing from Philadelphia (PHL), United States and arriving at Knoxville (TYS), United States. The flight distance is about 892.03 km or 554.28 miles and flight time is 1 hours 41 minutes. Get the latest status of AA4910 / AAL4910 here.
Update on May 24, 2023, 3:24 p.m.
Lastest Status
N/A
PHL | TYS |
Distance: 892.03 km / 554.28 miles or 481.66 nautical miles.
Departure Philadelphia International Airport
Scheduled Departure: 9:22 a.m.
Departure Terminal : Gate None
Arrival Knoxville Airport
Scheduled Arrival: 11:38 a.m.
Arrival Terminal : Gate None
Flight AA4910 detail information
Type | Domestic Flight |
Route | Departure Philadelphia (PHL), United States and arriving at Knoxville (TYS), United States |
Airlines | American Airlines (AA) |
Aircraft | E145 |
Flight Duration | 1 hours 41 minutes |
Flight Distance | 892.03 km /554.28 miles |
Operating Days | Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday |
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AA4910 Airports
Departures |
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Airport: Philadelphia International Airport, United States |
ICAO Code: PHL |
PHL Current time: 04:23 29-Apr-2024 |
Arrivals |
Airport: Knoxville Airport, United States |
ICAO Code: TYS |
TYS Current time: 04:23 29-Apr-2024 |