American Airlines AA4875 Flight Status Tracker
AA4875 is a domestic flight operated by American Airlines. AA4875 is departing from Montgomery (MGM), United States and arriving at Charlotte (CLT), United States. The flight distance is about 600.25 km or 372.98 miles and flight time is 48 minutes. Get the latest status of AA4875 / AAL4875 here.
Update on May 4, 2024, 9:26 p.m.
Lastest Status
N/A
MGM | CLT |
Distance: 600.25 km / 372.98 miles or 324.11 nautical miles.
Departure Montgomery Dannelly Airport
Scheduled Departure: 8:30 a.m.
Departure Terminal : Gate None
Arrival Charlotte Douglas Airport
Scheduled Arrival: 11:55 a.m.
Arrival Terminal : Gate None
Flight AA4875 detail information
Type | Domestic Flight |
Route | Departure Montgomery (MGM), United States and arriving at Charlotte (CLT), United States |
Airlines | American Airlines (AA) |
Aircraft | ER4 |
Flight Duration | 48 minutes |
Flight Distance | 600.25 km /372.98 miles |
Operating Days | Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday |
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AA4875 Airports
Departures |
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Airport: Montgomery Dannelly Airport, United States |
ICAO Code: MGM |
MGM Current time: 21:48 06-May-2024 |
Arrivals |
Airport: Charlotte Douglas Airport, United States |
ICAO Code: CLT |
CLT Current time: 22:48 06-May-2024 |