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American Airlines AA4800 Flight Status Tracker

AA4800 is a domestic flight operated by American Airlines. AA4800 is departing from Greenville (GSP), United States and arriving at Philadelphia (PHL), United States. The flight distance is about 828.74 km or 514.96 miles and flight time is 1 hours 25 minutes. Get the latest status of AA4800 / AAL4800 here.

Update on Dec. 28, 2025, 4:56 a.m.
Lastest Status
Arrived Delayed by 50m
GSP
PHL
Distance: 828.74 km / 514.96 miles or 447.48 nautical miles.
Departure Greenville Spartanburg International Airport

Actual Departure: 12:46

Scheduled Departure: 11:44

Departure Terminal : Gate None

Arrival Philadelphia International Airport

Actual Arrival: 16:06

Scheduled Arrival: 15:16

Arrival Terminal : 2 Gate None

Flight AA4800 detail information

Type Domestic Flight
Route Departure Greenville (GSP), United States and arriving at Philadelphia (PHL), United States
Airlines American Airlines (AA)
Aircraft E145
Flight Duration 1 hours 25 minutes
Flight Distance 828.74 km /514.96 miles
Operating Days Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday

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AA4800 Airports

Departures
Airport: Greenville Spartanburg International Airport, United States
ICAO Code: GSP
GSP Current time: 01:50 28-Dec-2025
Arrivals
Airport: Philadelphia International Airport, United States
ICAO Code: PHL
PHL Current time: 01:50 28-Dec-2025