WestJet WS4680 Flight Status Tracker
WS4680 is a domestic flight operated by WestJet. WS4680 is departing from Calgary (YYC), Canada and arriving at Kamloops (YKA), Canada. The flight distance is about 454.59 km or 282.47 miles and flight time is 48 minutes. Get the latest status of WS4680 / WJA4680 here.
Update on Oct. 15, 2022, 7:02 a.m.
Lastest Status
N/A
| YYC | YKA |
Distance: 454.59 km / 282.47 miles or 245.46 nautical miles.
Departure Calgary International Airport
Scheduled Departure: 4:15 p.m.
Departure Terminal : None Gate A16
Arrival Kamloops Airport
Scheduled Arrival: 5 p.m.
Arrival Terminal : None Gate 2
Flight WS4680 detail information
| Type | Domestic Flight |
| Route | Departure Calgary (YYC), Canada and arriving at Kamloops (YKA), Canada |
| Airlines | WestJet (WS) |
| Aircraft | Boeing 737-7CT |
| Flight Duration | 48 minutes |
| Flight Distance | 454.59 km /282.47 miles |
| Operating Days | Thursday |
Find more flight status
WS4680 Airports
| Departures |
|---|
| Airport: Calgary International Airport, Canada |
| ICAO Code: YYC |
| YYC Current time: 10:31 11-May-2024 |
| Arrivals |
| Airport: Kamloops Airport, Canada |
| ICAO Code: YKA |
| YKA Current time: 09:31 11-May-2024 |