Virgin Atlantic VS4738 Flight Status Tracker
VS4738 is a domestic flight operated by Virgin Atlantic. VS4738 is departing from Cleveland (CLE), United States and arriving at New York (JFK), United States. The flight distance is about 682.12 km or 423.85 miles and flight time is 1 hours 41 minutes. Get the latest status of VS4738 / VIR4738 here.
Update on March 8, 2024, 3:56 p.m.
Lastest Status
N/A
| CLE | JFK |
Distance: 682.12 km / 423.85 miles or 368.32 nautical miles.
Departure Cleveland Hopkins International Airport
Scheduled Departure: 5:06 p.m.
Departure Terminal : None Gate None
Arrival John F. Kennedy International Airport
Scheduled Arrival: 6:55 p.m.
Arrival Terminal : None Gate None
Flight VS4738 detail information
| Type | Domestic Flight |
| Route | Departure Cleveland (CLE), United States and arriving at New York (JFK), United States |
| Airlines | Virgin Atlantic (VS) |
| Aircraft | ERJ |
| Flight Duration | 1 hours 41 minutes |
| Flight Distance | 682.12 km /423.85 miles |
| Operating Days |
Find more flight status
VS4738 Airports
| Departures |
|---|
| Airport: Cleveland Hopkins International Airport, United States |
| ICAO Code: CLE |
| CLE Current time: 10:44 22-Dec-2025 |
| Arrivals |
| Airport: John F. Kennedy International Airport, United States |
| ICAO Code: JFK |
| JFK Current time: 10:44 22-Dec-2025 |