Air India AI9708 Flight Status Tracker
AI9708 is a international flight operated by Air India. AI9708 is departing from Mahe Island (SEZ), Seychelles and arriving at Abu Dhabi (AUH), United Arab Emirates. The flight distance is about 15203.43 km or 9446.97 miles and flight time is 35 minutes. Get the latest status of AI9708 / AIC9708 here.
Update on Jan. 16, 2026, 7:33 a.m.
Lastest Status
Arrived Delayed by 30m
| SEZ | AUH |
Distance: 15203.43 km / 9446.97 miles or 8209.19 nautical miles.
Departure Mahe Island Airport
Actual Departure: 09:58
Scheduled Departure: 09:30
Departure Terminal : I Gate None
Arrival Abu Dhabi International Airport
Actual Arrival: 12:35
Scheduled Arrival: 12:05
Arrival Terminal : 3 Gate None
Flight AI9708 detail information
| Type | International Flight |
| Route | Departure Mahe Island (SEZ), Seychelles and arriving at Abu Dhabi (AUH), United Arab Emirates |
| Airlines | Air India (AI) |
| Aircraft | |
| Flight Duration | 35 minutes |
| Flight Distance | 15203.43 km /9446.97 miles |
| Operating Days | Tuesday, Thursday, Saturday, Sunday |
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AI9708 Airports
| Departures |
|---|
| Airport: Mahe Island Airport, Seychelles |
| ICAO Code: SEZ |
| SEZ Current time: 14:40 16-Jan-2026 |
| Arrivals |
| Airport: Abu Dhabi International Airport, United Arab Emirates |
| ICAO Code: AUH |
| AUH Current time: 04:40 16-Jan-2026 |