Air Canada AC7398 Flight Status Tracker
AC7398 is a international flight operated by Air Canada. AC7398 is departing from Toronto (YYZ), Canada and arriving at Jacksonville (JAX), United States. The flight distance is about 1475.27 km or 916.69 miles and flight time is 2 hours 30 minutes. Get the latest status of AC7398 / ACA7398 here.
Update on Dec. 8, 2019, 12:08 p.m.
Lastest Status
N/A
| YYZ | JAX |
Distance: 1475.27 km / 916.69 miles or 796.58 nautical miles.
Departure Toronto Pearson International Airport
Scheduled Departure: 3:40 p.m.
Departure Terminal : 3 Gate None
Arrival Jacksonville International Airport
Scheduled Arrival: 5:06 p.m.
Arrival Terminal : 1 Gate None
Flight AC7398 detail information
| Type | International Flight |
| Route | Departure Toronto (YYZ), Canada and arriving at Jacksonville (JAX), United States |
| Airlines | Air Canada (AC) |
| Aircraft | CRJ |
| Flight Duration | 2 hours 30 minutes |
| Flight Distance | 1475.27 km /916.69 miles |
| Operating Days | Monday, Tuesday, Thursday, Friday, Saturday, Sunday |
Find more flight status
AC7398 Airports
| Departures |
|---|
| Airport: Toronto Pearson International Airport, Canada |
| ICAO Code: YYZ |
| YYZ Current time: 14:14 27-Apr-2024 |
| Arrivals |
| Airport: Jacksonville International Airport, United States |
| ICAO Code: JAX |
| JAX Current time: 14:14 27-Apr-2024 |