Air Canada AC6866 Flight Status Tracker
AC6866 is a domestic flight operated by Air Canada. AC6866 is departing from Johannesburg (JNB), South Africa and arriving at Port Elizabeth (PLZ), South Africa. The flight distance is about 905.84 km or 562.86 miles and flight time is 1 hours 55 minutes. Get the latest status of AC6866 / ACA6866 here.
Update on Feb. 17, 2020, 3:54 a.m.
Lastest Status
N/A
| JNB | PLZ |
Distance: 905.84 km / 562.86 miles or 489.11 nautical miles.
Departure Johannesburg OR Tambo Airport
Scheduled Departure: 10:55 a.m.
Departure Terminal : Gate None
Arrival Port Elizabeth Airport
Scheduled Arrival: 12:30 p.m.
Arrival Terminal : Gate None
Flight AC6866 detail information
| Type | Domestic Flight |
| Route | Departure Johannesburg (JNB), South Africa and arriving at Port Elizabeth (PLZ), South Africa |
| Airlines | Air Canada (AC) |
| Aircraft | 320 |
| Flight Duration | 1 hours 55 minutes |
| Flight Distance | 905.84 km /562.86 miles |
| Operating Days |
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AC6866 Airports
| Departures |
|---|
| Airport: Johannesburg OR Tambo Airport, South Africa |
| ICAO Code: JNB |
| JNB Current time: 06:01 09-May-2024 |
| Arrivals |
| Airport: Port Elizabeth Airport, South Africa |
| ICAO Code: PLZ |
| PLZ Current time: 06:01 09-May-2024 |