Air Canada AC48 Flight Status Tracker
AC48 is a international flight operated by Air Canada. AC48 is departing from Toronto (YYZ), Canada and arriving at New Delhi (DEL), India. The flight distance is about 11661.80 km or 7246.31 miles and flight time is 5 hours 45 minutes. Get the latest status of AC48 / ACA48 here.
Update on April 20, 2022, 4:38 a.m.
Lastest Status
N/A
| YYZ | DEL |
Distance: 11661.80 km / 7246.31 miles or 6296.87 nautical miles.
Departure Toronto Pearson International Airport
Scheduled Departure: 10 a.m.
Departure Terminal : A Gate None
Arrival Delhi Airport
Scheduled Arrival: 10:25 a.m.
Arrival Terminal : Gate None
Flight AC48 detail information
| Type | International Flight |
| Route | Departure Toronto (YYZ), Canada and arriving at New Delhi (DEL), India |
| Airlines | Air Canada (AC) |
| Aircraft | B77L |
| Flight Duration | 5 hours 45 minutes |
| Flight Distance | 11661.80 km /7246.31 miles |
| Operating Days |
Find more flight status
AC48 Airports
| Departures |
|---|
| Airport: Toronto Pearson International Airport, Canada |
| ICAO Code: YYZ |
| YYZ Current time: 00:40 13-Dec-2025 |
| Arrivals |
| Airport: Delhi Airport, India |
| ICAO Code: DEL |
| DEL Current time: 11:10 13-Dec-2025 |