Air Canada AC4735 Flight Status Tracker
AC4735 is a domestic flight operated by Air Canada. AC4735 is departing from New York (EWR), United States and arriving at Jacksonville (JAX), United States. The flight distance is about 1318.88 km or 819.51 miles and flight time is 1 hours 39 minutes. Get the latest status of AC4735 / ACA4735 here.
Update on Nov. 4, 2025, 10:56 a.m.
Lastest Status
N/A
| EWR | JAX |
Distance: 1318.88 km / 819.51 miles or 712.14 nautical miles.
Departure Newark Liberty International Airport
Scheduled Departure: 6:25 a.m.
Departure Terminal : 1 Gate None
Arrival Jacksonville International Airport
Scheduled Arrival: 8:58 a.m.
Arrival Terminal : C Gate None
Flight AC4735 detail information
| Type | Domestic Flight |
| Route | Departure New York (EWR), United States and arriving at Jacksonville (JAX), United States |
| Airlines | Air Canada (AC) |
| Aircraft | E70 |
| Flight Duration | 1 hours 39 minutes |
| Flight Distance | 1318.88 km /819.51 miles |
| Operating Days |
Find more flight status
AC4735 Airports
| Departures |
|---|
| Airport: Newark Liberty International Airport, United States |
| ICAO Code: EWR |
| EWR Current time: 19:29 20-Nov-2025 |
| Arrivals |
| Airport: Jacksonville International Airport, United States |
| ICAO Code: JAX |
| JAX Current time: 19:29 20-Nov-2025 |