Air Transport International 8C4724 Flight Status Tracker
8C4724 is a domestic flight operated by Air Transport International. 8C4724 is departing from Allentown (ABE), United States and arriving at Fort Worth (AFW), United States. The flight distance is about 2122.04 km or 1318.57 miles and flight time is 0 minutes. Get the latest status of 8C4724 / ATN4724 here.
Update on Dec. 8, 2019, 5:58 p.m.
Lastest Status
N/A
| ABE | AFW |
Distance: 2122.04 km / 1318.57 miles or 1145.81 nautical miles.
Departure Allentown Airport
Scheduled Departure: None
Departure Terminal : None Gate None
Arrival Fort Worth Alliance Airport
Scheduled Arrival: None
Arrival Terminal : None Gate None
Flight 8C4724 detail information
| Type | Domestic Flight |
| Route | Departure Allentown (ABE), United States and arriving at Fort Worth (AFW), United States |
| Airlines | Air Transport International (8C) |
| Aircraft | B763 |
| Flight Duration | 0 minutes |
| Flight Distance | 2122.04 km /1318.57 miles |
| Operating Days |
Find more flight status
8C4724 Airports
| Departures |
|---|
| Airport: Allentown Airport, United States |
| ICAO Code: ABE |
| ABE Current time: 21:49 20-Nov-2025 |
| Arrivals |
| Airport: Fort Worth Alliance Airport, United States |
| ICAO Code: AFW |
| AFW Current time: 20:49 20-Nov-2025 |