Allegiant Air G4869 Flight Status Tracker

G4869 is a domestic flight operated by Allegiant Air. G4869 is departing from Knoxville (TYS), United States and arriving at Clearwater (PIE), United States. The flight distance is about 883.79 km or 549.16 miles and flight time is 1 hours 38 minutes. Get the latest status of G4869 / AAY869 here.

Update on May 15, 2024, 8:41 p.m.

Lastest Status

N/A
G4 Flight Status
TYS
Departure
Knoxville Airport
Scheduled Departure:
10:10 a.m.
Departure Terminal:
2 Gate None
Flight Status
Distance:
883.79 km / 549.16 miles or 477.21 nautical miles.
PIE
Arrival
St. Pete - Clearwater International Airport
Scheduled Arrival:
12:48 p.m.
Departure Terminal:
Gate None

Flight G4869 detail information

  • Type Domestic Flight
  • Route Departure Knoxville (TYS), United States and arriving at Clearwater (PIE), United States
  • Airlines Allegiant Air (G4)
  • Aircraft A320
  • Flight Duration 1 hours 38 minutes
  • Flight Distance 883.79 km /549.16 miles
  • Operating Days Monday, Friday

G4869 Airports

Departures
  • Airport: Knoxville Airport, United States
  • ICAO Code: TYS
  • TYS Current time: 22:29 28-May-2024
Arrivals
  • Airport: St. Pete - Clearwater International Airport, United States
  • ICAO Code: PIE
  • PIE Current time: 22:29 28-May-2024