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Allegiant Air G48002 Flight Status Tracker

G48002 is a domestic flight operated by Allegiant Air. G48002 is departing from Panama City (PAM), United States and arriving at Goldsboro (GSB), United States. The flight distance is about 922.33 km or 573.11 miles and flight time is 4 hours 34 minutes. Get the latest status of G48002 / AAY8002 here.

Update on Dec. 10, 2022, 9:33 p.m.

Lastest Status

N/A
G4 Flight Status
PAM
Departure
Tyndall Air Force Base Airport
Scheduled Departure:
2:05 p.m.
Departure Terminal:
N Gate None
Flight Status
Distance:
922.33 km / 573.11 miles or 498.02 nautical miles.
GSB
Arrival
Seymour Johnson Air Force Base Airport
Scheduled Arrival:
5:15 p.m.
Departure Terminal:
Gate None

Flight G48002 detail information

  • Type Domestic Flight
  • Route Departure Panama City (PAM), United States and arriving at Goldsboro (GSB), United States
  • Airlines Allegiant Air (G4)
  • Aircraft A320
  • Flight Duration 4 hours 34 minutes
  • Flight Distance 922.33 km /573.11 miles
  • Operating Days Wednesday

G48002 Airports

Departures
  • Airport: Tyndall Air Force Base Airport, United States
  • ICAO Code: PAM
  • PAM Current time: 11:25 26-Apr-2024
Arrivals
  • Airport: Seymour Johnson Air Force Base Airport, United States
  • ICAO Code: GSB
  • GSB Current time: 12:25 26-Apr-2024

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