G4403 is a domestic flight operated by Allegiant Air. G4403 is departing from Knoxville (TYS), United States and arriving at Clearwater (PIE), United States.
The flight distance is about 884 km or 549 miles and flight time is
3 hours 1 minutes. Get the latest status of G4403 / AAY403 here.
Update on Nov. 30, 2019, 4:26 a.m.
Distance: 884 km / 549 miles or 477 nautical miles.
Departure Knoxville Airport
Arrival St. Pete - Clearwater International Airport
|Scheduled Departure: 9:20 p.m.
||Scheduled Arrival: 11:05 p.m.
|Departure Terminal : Gate None
||Arrival Terminal : 2 Gate None