Air India AI9708 Flight Status Tracker
AI9708 is a international flight operated by Air India. AI9708 is departing from Mahe Island (SEZ), Seychelles and arriving at Abu Dhabi (AUH), United Arab Emirates. The flight distance is about 15203.43 km or 9446.97 miles and flight time is 35 minutes. Get the latest status of AI9708 / AIC9708 here.
Update on Feb. 15, 2019, 7:19 p.m.
Lastest Status
N/A
SEZ
Departure
Mahe Island Airport
Scheduled Departure:
2:50 p.m.
Departure Terminal:
I Gate None
Distance:
15203.43 km / 9446.97 miles or 8209.19 nautical miles.
AUH
Arrival
Abu Dhabi International Airport
Scheduled Arrival:
7:25 p.m.
Departure Terminal:
3 Gate None
Flight AI9708 detail information
- Type International Flight
- Route Departure Mahe Island (SEZ), Seychelles and arriving at Abu Dhabi (AUH), United Arab Emirates
- Airlines Air India (AI)
- Aircraft
- Flight Duration 35 minutes
- Flight Distance 15203.43 km /9446.97 miles
- Operating Days Tuesday, Thursday, Saturday, Sunday
AI9708 Airports
Departures
- Airport: Mahe Island Airport, Seychelles
- ICAO Code: SEZ
- SEZ Current time: 09:34 25-Apr-2024
Arrivals
- Airport: Abu Dhabi International Airport, United Arab Emirates
- ICAO Code: AUH
- AUH Current time: 00:34 25-Apr-2024
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