Flight distance from San Angelo to New York
2587 kilometers/1607 miles
or 1397 nautical miles.
Your flight will depart from San Angelo airport and land at New York airport.
| City: | San Angelo (SJT) | New York (NYC) |
|---|---|---|
| Latitude: | 31.413194 | 40.730926 |
| Longitude: | -100.463888 | -73.972037 |
| Country: | United States | United States |
| Timezone: | America/Chicago | America/New_York |
| Current time:: | 19:41 01-Apr-2026 | 19:41 01-Apr-2026 |
How far is between San Angelo and New York?
- Your starting point San Angelo, United States is located at 31.413194,-100.463888
- Your ending point New York, United States is located at 40.730926,-73.972037
- l distance from San Angelo to New York is 2587 kms equals to miles and 1397 nautical miles.
- Flight time from San Angelo to New York is 20 hours 42 minutes
Click here to get detail flight schedules from San Angelo to New York
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