WestJet WS4680 Flight Status Tracker
WS4680 is a domestic flight operated by WestJet. WS4680 is departing from Calgary (YYC), Canada and arriving at Kamloops (YKA), Canada. The flight distance is about 454.59 km or 282.47 miles and flight time is 48 minutes. Get the latest status of WS4680 / WJA4680 here.
Update on Oct. 15, 2022, 7:02 a.m.
Lastest Status
N/A
YYC
Departure
Calgary International Airport
Scheduled Departure:
4:15 p.m.
Departure Terminal:
None Gate A16
Distance:
454.59 km / 282.47 miles or 245.46 nautical miles.
YKA
Arrival
Kamloops Airport
Scheduled Arrival:
5 p.m.
Departure Terminal:
None Gate 2
Flight WS4680 detail information
- Type Domestic Flight
- Route Departure Calgary (YYC), Canada and arriving at Kamloops (YKA), Canada
- Airlines WestJet (WS)
- Aircraft Boeing 737-7CT
- Flight Duration 48 minutes
- Flight Distance 454.59 km /282.47 miles
- Operating Days Thursday
WS4680 Airports
Departures
- Airport: Calgary International Airport, Canada
- ICAO Code: YYC
- YYC Current time: 18:46 27-Apr-2024
Arrivals
- Airport: Kamloops Airport, Canada
- ICAO Code: YKA
- YKA Current time: 17:46 27-Apr-2024