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Virgin Atlantic VS4738 Flight Status Tracker

VS4738 is a domestic flight operated by Virgin Atlantic. VS4738 is departing from Cleveland (CLE), United States and arriving at New York (JFK), United States. The flight distance is about 682.12 km or 423.85 miles and flight time is 1 hours 41 minutes. Get the latest status of VS4738 / VIR4738 here.

Update on March 8, 2024, 3:56 p.m.

Lastest Status

N/A
VS Flight Status
CLE
Departure
Cleveland Hopkins International Airport
Scheduled Departure:
5:06 p.m.
Departure Terminal:
None Gate None
Flight Status
Distance:
682.12 km / 423.85 miles or 368.32 nautical miles.
JFK
Arrival
John F. Kennedy International Airport
Scheduled Arrival:
6:55 p.m.
Departure Terminal:
None Gate None

Flight VS4738 detail information

  • Type Domestic Flight
  • Route Departure Cleveland (CLE), United States and arriving at New York (JFK), United States
  • Airlines Virgin Atlantic (VS)
  • Aircraft ERJ
  • Flight Duration 1 hours 41 minutes
  • Flight Distance 682.12 km /423.85 miles
  • Operating Days

VS4738 Airports

Departures
  • Airport: Cleveland Hopkins International Airport, United States
  • ICAO Code: CLE
  • CLE Current time: 18:45 25-Apr-2024
Arrivals
  • Airport: John F. Kennedy International Airport, United States
  • ICAO Code: JFK
  • JFK Current time: 18:45 25-Apr-2024

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