AF5808 is a domestic flight operated by Air France. AF5808 is departing from New York (JFK), United States and arriving at Tampa (TPA), United States.
The flight distance is about 1,618 km or 1,005 miles and flight time is
3 hours 12 minutes. Get the latest status of AF5808 / 5808 here.
Update on Dec. 10, 2018, 7:44 a.m.
Distance: 1,618 km / 1,005 miles or 874 nautical miles.
Departure John F. Kennedy International Airport
Arrival Tampa International Airport
|Scheduled Departure: 7:30 p.m.
||Scheduled Arrival: 10:34 p.m.
|Departure Terminal : 4 Gate None
||Arrival Terminal : None Gate None