Air Canada AC7398 Flight Status Tracker
AC7398 is a international flight operated by Air Canada. AC7398 is departing from Toronto (YYZ), Canada and arriving at Jacksonville (JAX), United States. The flight distance is about 1475.27 km or 916.69 miles and flight time is 2 hours 30 minutes. Get the latest status of AC7398 / ACA7398 here.
Update on Dec. 8, 2019, 12:08 p.m.
Lastest Status
N/A
YYZ
Departure
Toronto Pearson International Airport
Scheduled Departure:
3:40 p.m.
Departure Terminal:
3 Gate None
Distance:
1475.27 km / 916.69 miles or 796.58 nautical miles.
JAX
Arrival
Jacksonville International Airport
Scheduled Arrival:
5:06 p.m.
Departure Terminal:
1 Gate None
Flight AC7398 detail information
- Type International Flight
- Route Departure Toronto (YYZ), Canada and arriving at Jacksonville (JAX), United States
- Airlines Air Canada (AC)
- Aircraft CRJ
- Flight Duration 2 hours 30 minutes
- Flight Distance 1475.27 km /916.69 miles
- Operating Days Monday, Tuesday, Thursday, Friday, Saturday, Sunday
AC7398 Airports
Departures
- Airport: Toronto Pearson International Airport, Canada
- ICAO Code: YYZ
- YYZ Current time: 21:10 28-Mar-2024
Arrivals
- Airport: Jacksonville International Airport, United States
- ICAO Code: JAX
- JAX Current time: 21:10 28-Mar-2024