Air Canada AC6866 Flight Status Tracker
AC6866 is a domestic flight operated by Air Canada. AC6866 is departing from Johannesburg (JNB), South Africa and arriving at Port Elizabeth (PLZ), South Africa. The flight distance is about 905.84 km or 562.86 miles and flight time is 1 hours 55 minutes. Get the latest status of AC6866 / ACA6866 here.
Update on Feb. 17, 2020, 3:54 a.m.
Lastest Status
N/A
JNB
Departure
Johannesburg OR Tambo Airport
Scheduled Departure:
10:55 a.m.
Departure Terminal:
Gate None
Distance:
905.84 km / 562.86 miles or 489.11 nautical miles.
PLZ
Arrival
Port Elizabeth Airport
Scheduled Arrival:
12:30 p.m.
Departure Terminal:
Gate None
Flight AC6866 detail information
- Type Domestic Flight
- Route Departure Johannesburg (JNB), South Africa and arriving at Port Elizabeth (PLZ), South Africa
- Airlines Air Canada (AC)
- Aircraft 320
- Flight Duration 1 hours 55 minutes
- Flight Distance 905.84 km /562.86 miles
- Operating Days
AC6866 Airports
Departures
- Airport: Johannesburg OR Tambo Airport, South Africa
- ICAO Code: JNB
- JNB Current time: 11:25 27-Apr-2024
Arrivals
- Airport: Port Elizabeth Airport, South Africa
- ICAO Code: PLZ
- PLZ Current time: 11:25 27-Apr-2024
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