Air Canada AC4735 Flight Status Tracker
AC4735 is a domestic flight operated by Air Canada. AC4735 is departing from New York (EWR), United States and arriving at Jacksonville (JAX), United States. The flight distance is about 1318.88 km or 819.51 miles and flight time is 1 hours 39 minutes. Get the latest status of AC4735 / ACA4735 here.
Update on April 25, 2024, 7:47 a.m.
Lastest Status
Arrived On time
EWR
Departure
Newark Liberty International Airport
Scheduled Departure:
07:55
Actual Departure:
07:50
Departure Terminal:
1 Gate None
Distance:
1318.88 km / 819.51 miles or 712.14 nautical miles.
JAX
Arrival
Jacksonville International Airport
Scheduled Arrival:
10:23
Actual Arrival:
10:06
Departure Terminal:
C Gate None
Flight AC4735 detail information
- Type Domestic Flight
- Route Departure New York (EWR), United States and arriving at Jacksonville (JAX), United States
- Airlines Air Canada (AC)
- Aircraft E70
- Flight Duration 1 hours 39 minutes
- Flight Distance 1318.88 km /819.51 miles
- Operating Days
AC4735 Airports
Departures
- Airport: Newark Liberty International Airport, United States
- ICAO Code: EWR
- EWR Current time: 10:11 25-Apr-2024
Arrivals
- Airport: Jacksonville International Airport, United States
- ICAO Code: JAX
- JAX Current time: 10:11 25-Apr-2024