G41223 is a domestic flight operated by Allegiant Air. G41223 is departing from Knoxville (TYS), United States and arriving at Clearwater (PIE), United States.
The flight distance is about 884 km or 549 miles and flight time is
1 hours 38 minutes. Get the latest status of G41223 / 1223 here.
Update on Dec. 17, 2018, 9:19 a.m.
Distance: 884 km / 549 miles or 477 nautical miles.
Departure Knoxville Airport
Arrival St. Pete - Clearwater International Airport
|Scheduled Departure: 1:32 p.m.
||Scheduled Arrival: 3:10 p.m.
|Departure Terminal : N/A Gate None
||Arrival Terminal : N/A Gate None